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Two long, straight, parallel wires are 1...

Two long, straight, parallel wires are 1.00m apart (as shown in Fig). The upper wire carries a current `I_1` of 6.00A into the plane of the paper.

What is the magnitude of the net field at S?

A

`4.1xx10^-6T`

B

`1.6xx10^-6T`

C

`3.2xx10^-6T`

D

`2.1xx10^-6T`

Text Solution

Verified by Experts

The correct Answer is:
D
(d) The magnitude of the field at S is given by the sum of the squres
of the two fields because they are at right angles. So,
`B_S=sqrt(B_1^2+B_2^2)=(mu_0)/(2pi)sqrt(((I_1)/(r_1))^2+((I_2)/(r_2))^2)`
`=(mu_0)/(2pi)sqrt(((6.00A)/(0.500m)-(2.00A)/(1.50m)))`
`=2.1xx10^-6T`
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Knowledge Check

  • Two long, straight, parallel wires are 1.00m apart (as shown in Fig). The upper wire carries a current I_1 of 6.00A into the plane of the paper. What is the magnitude of the net field at Q?

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    `2.13xx10^-6T`
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