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An elevator carrying a charge of 0.5C is...

An elevator carrying a charge of 0.5C is moving down with a velocity of `5xx10^3ms^-1`. The elevator is 4m from the bottom and 3m horizontally from P as shown in Fig. What magnetic field (`muT`) does it produce at point P

Text Solution

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The correct Answer is:
`6`
(6) According to Biot-Savart law,
`B=(mu_0)/(4pi) (qv)/(r^2) sin theta=(10^-7xx0.5xx5xx10^3)/(5^2) (3/5)=6muT`
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