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The figure shows a circular loop of radi...

The figure shows a circular loop of radius `a` with two long parallel wires `(numbered 1 and 2)` all in the plane of the paper . The distance of each wire from the centre of the loop is `d`. The loop and the wire are carrying the same current `I`. The current in the loop is in the counterclockwise direction if seen from above.
(q) The magnetic fields(B) at `P` due to the currents in the wires are in opposite directions.
(r) There is no magnetic field at `P`.
(s) The wires repel each other.

(5) Consider `dgtgta`, and the loop is rotated about its diameter parallel to the wires by `30^(@)` from the position shown in the figure. If the currents in the wire are in the opposite directions, the torque on the loop at its new position will be ( assume that the net field due to the wires is constant over the loop).

A

`(mu_0I^2a^2)/d`

B

`(mu_0I^2a^2)/(2d)`

C

`(sqrt3mu_0I^2a^2)/d`

D

`(sqrt3mu_0I^2a^2)/(2d)`

Text Solution

Verified by Experts

The correct Answer is:
B
(b) : `B=2((mu_0i)/(2pid))`
`:. tau=ipid^2(mu_0)/(pid) sin(30^@)=(mu_0I^2a)/(2d)`
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