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During the decay of current in an LR cir...

During the decay of current in an `LR` circuit, if the current falls to `eta` times the intial value in time `T`, then determine the value of time constane.

Text Solution

Verified by Experts

we know that `I = I_(max) e^(-t//T)`
At `t = T, I = eta I_(max_(-t//T))`
`eta I_(max) = I_(max)e`
or `e^(-t//T) = eta, T = (t)/(In |(1)/(n)|)`
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Knowledge Check

  • When a choke coil carrying a steady current is short circuited, the current in it decreases to beta(lt1) times its initial value in a time T . The time constant of the choke coil is

    A
    `T/beta`
    B
    `T/(ln(1/beta)`
    C
    `T/(lnbeta)`
    D
    `T ln beta`

  • The current in an L - R circuit in a time t = 2L / R reduces to-

    A
    `336.5%` of maximum
    B
    `13.5%` of maximum
    C
    `0.50%` of maximum
    D
    `63.2%` of maximum

  • Time constant of LR circuit will be

    A
    `(L)/(R )`
    B
    `(2L)/(R )`
    C
    `(L)/(2R)`
    D
    None of these

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