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A toroid is wound over a circular core. ...

A toroid is wound over a circular core. Radius of each turn is `r` and radius of toroid is `R (gt gt r)`. The coefficient of self-inductance of the toroid is given by

A

`L = (mu_(0)Nr^(2))/(2R)`

B

`L = (mu_(0)Nr)/(2R)`

C

`L = (mu_(0)Nr^(2))/(R )`

D

`L = (mu_(0)N^(2)r^(2))/(2R)`

Text Solution

Verified by Experts

The correct Answer is:
D

`L = (phi)/(I),phi = NAB`
`N = mu_(0)nI`
where `n = (N)/(2 pi R)`
`:. phi = Npi r^(2) (mu_(0)(N)/(2 piR)I)`
`phi = (mu_(0)N^(2)r^(2)I)/(2R)`
`L = (phi)/(I) = (mu_(0)N^(2)r^(2))/(2R)`
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