In the given circuit, find the current through the `5 mH` inductor in steady state.

Options

A. `(2)/(3) A`
B. `(8)/(3) A`
C. `(1)/(3) A`
D. `(2)/(3) A`

Answer

B

Explanation

Inductors `5 mH` and `10 mH` are connected in parallel, hence equivalent inductance `L_(eq) = (5 xx 10)/(5 + 10) = (50)/(15) = (10)/(3) mH`
Current at steady state, `I = (20)/(5) = 4A`
As `L_(1)` and `L_(2)` are in parallel
`I_(1) = I(L_(2)/(L_(1) + L_(2))) = 4 [(10)/(10 + 5)] = (8)/(3) A`