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A closed loop of cross-sectional area 10...

A closed loop of cross-sectional area `10^(-2) m^(2)` which has inductance `L = 10 mH` and negligible resistance is placed ti time- varying magnetic field. Figure shows the variation of `B` with time for the intervel `4 s`. The field is perpendicular to the plane of the loop (given at `t = 0`, `B = 0`, `I = 0)`. The value of the maximum current induced in the loop is

A

`0.1 mA`

B

`10 mA`

C

`100 mA`

D

Date insufficient

Text Solution

Verified by Experts

The correct Answer is:
C

Induced e.m.f. `e = L(dI)/(dt) = A (dB)/(dt)`
`rArr int_(0)^(1) dI = int_(0)^(B) (A)/(L) dB rArr I = (A)/(L) B`
`rArr I_(max) = (A)/(L) B_(max) = (10^(-2))/(10 xx 10^(-3)) xx 0.1 = 0.1 A = 100 mA`
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