The cell in the circuit shows in Fig is ideal. The coil has an inductance of `4 mH` and a resistance of `2 mOmega`. The switch is closed at `t = 0`. The amount of energy stored in the inductor at `t = 2 s` is (take `e = 3)`

Options

A. `(4)/(3) J`
B. `(8)/(9) xx 10^(3) J`
C. `(8)/(9) xx 10^(3) J`
D. `2 xx 10^(3) J`

Answer

B

Explanation

Use `I = (E)/(R ) [1 - e^(-t//tau)]` and `U = (1)/(2) Li^(2)`