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In the circuit shows in Fig the switch i...

In the circuit shows in Fig the switch is closed at `t = 0`.

A

At `t = 0,I_(1) = I_(2) = 0`

B

At any time `t, (I_(0))/(I_(2)) = (L_(2))/(L_(1))`

C

At any time t, `I_(1) + I_(2) = (epsilon)/(R )`

D

At `t = oo, I_(1)` and `I_(2)` are independent of `L_(1)` and `L_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A, B
The coils are in parallel, so
`L_(1) (dI_(1))/(dt) = L_(2) (dI_(2))/(dt) rArr int L_(1) dI_(1) = int L_(1) dI_(2)`
`rArr` Initially `I_(1) = 0`, `I_(2) = 0 rArr C = 0`
So `L_(1) I_(1) = L_(2)I_(2)`
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