A capacitor of capacity `2 muF` is charged to a potential difference of `12 V`. It is then connected across an inductor of inductance `6 mu H`. What is the current (in `A`) in the circuit at a time when the potential difference across the capacitor is `6.0 V`?

Answer

`(6)`

Explanation

From energy conservation: `(1)/(2) CV_(0)^(2) = (1)/(2) Cv^(2) + (1)/(2) LI^(2)`
`rArr (1)/(2) xx 2xx 10^(-6) xx 12^(2) = (1)/(2) xx 2 xx 10^(-6) xx 6^(2) + (1)/(2) xx 6 xx 10^(-6) I^(2)`
`rArr I = 6 A`