The plate on the back of a personal computer says that it draws 2.7 A from a 120-V, 60-Hz line. For this computer, what is (a) the average of the square of the current, (b) the current amplitude, (c ) the average current for a positive half cycle, and (d ) the average current for a full cycle?

Explanation

(a) The current given is the rms value: `I_(rms)=2.7 A`.The average of the sqaure of the square of the current is nothing but `(I_(rms))^(2)`.
So, `(I-(rms))^(2)=(2.7 A)^(2)=7.3 A^(2)`
(b) The current amplitude `I_(0)` is
`I_(0)=sqrt(2)(2.7A)=3.8A`
(c ) For a positive half cycle, `I_(av)=(2I_(0))/(pi)=(2xx3.8)/(pi)=2.42 A`
(d) For a full cycle, `I_(av)=0`.