An LCR circuit contains resistance of `100 Omega` and a supply of 200V at 300 rad angular frequency. If only capacitance is taken out from the circuit and the rest of the circiut is joined, current lags behind the voltage by `60^(@)` . If, on the other hand , only inductor is taken out, the current flowing in the circuit is

Options

A. 1A
B. 1.5A
C. 2A
D. 2.5A

Answer

C

Explanation

According to the given question
`tan 60^(@) =(omega L)/(R ) and tan 60^(@) =(1//omega C)/(R )`
`:. (omega L)=(1//omega C)( "case of resonance")`
Now ` Z=sqrt(R^(2)+(omega L-(1)/(omega C))^(2))=100 Omega`
`:. I_(rms)=(E_(rms))/(Z) =(200 V)/(100 Omega)=2A`.