A sinusoidal alternating current of peak value `(I_0)` passes through a heater of resistance R. What is the mean power output of the heater?

Options

A. (A) `I_(0)^(2)R`
B. (B) `(I_(0)^(2)R)/(2)`
C. (C) `2I_(0)^(2)R`
D. (D) `sqrt(2)I_(0)^(2)R`

Answer

B

Explanation

Root mean square current of the sinusoidal waveform,
`I=(I_0)/(sqrt(2))`
Power output of the heater,
`P=I^(2)R =((I_0)/(sqrt(2)))^(2) R=(I_(0)^(2)R)/(2)`