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In the above question, the capacitive re...

In the above question, the capacitive reactance in the circuit is

A

`100 Omega`

B

`25 Omega`

C

`sqrt(125xx75)Omega`

D

`400 Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
Impadance `Z=(E_V)/(I_V) or Z = (200)/(2) = 100 Omega`
But ` Z^(2) = R^(2)+((1)/(omega c))^(2)`
or ` ((I)/(omega C))^(2) Z^(2) -R^(2) = (100)^(2) -(25)^(2) = 125 xx 75`
or, `X_(C) =(1)/(omega C) = sqrt(125 xx 75 ) Omega`.
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Knowledge Check

  • The capacitive reactance in an A.C. circuit is

    A
    effective resistance due to capacitor
    B
    effective wattage
    C
    effective voltage
    D
    none of the above

  • In the above question, the capacitance in the circuit is

    A
    `(100)/(100 pi)f`
    B
    `(25)/(100 pi)F`
    C
    `(sqrt(125 xx75))/(100 pi) F`
    D
    `(1)/(100 pi sqrt(125 xx 75))F`

  • An LCR series circuit with 100 Omega resistance is connected to an ac source of 200 V and angular frequency 300 rad/s. When only the capacitance is removed, the current lags behind the voltage by 60^@ . When only the inductance is removed, the current leads the voltage by 60^@ . when inductor is removed , capacitive reactance of the circuit is

    A
    `sqrt3xx50 Omega`
    B
    `100sqrt3Omega`
    C
    `50 sqrt3Omega`
    D
    `20 sqrt2Omega`

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