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In the above question, the capacitance i...

In the above question, the capacitance in the circuit is

A

`(100)/(100 pi)f`

B

`(25)/(100 pi)F`

C

`(sqrt(125 xx75))/(100 pi) F`

D

`(1)/(100 pi sqrt(125 xx 75))F`

Text Solution

Verified by Experts

The correct Answer is:
D
`(1)/(omega C) = sqrt(125 xx 75)`
Here `omega = 2 pi f = 2 pi xx 50 = 100 pi rad s^(-1)`
`:. C=(1)/(100 pi sqrt(125xx75))F`.
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