When an ac source of emf`e=E_(0) sin (100 t)` is connected across a circuit, the phase difference between emf e and currnet I in the circuit is observed to be `(pi)//(4)` as shown in fig. If the circuit consists possibly only of R-C or R-C of L-R series, find the relationship find the relationship between the two elements.

Options

A. `R=1 kOmega, C=10 (mu)F`
B. `R=1 kOmega, C=1(mu)F`
C. `R=1 kOmega,L=10 (mu)F`
D. `R=1 kOmega, L=1 (mu)F`

Answer

A

Explanation

Current leads emf so the circuit is R-C
`tan (phi) =X_(C )//R, phi=45^(@), R=1000 Omega , omega=100`
since `tan 45^(@) =(1)/(omega CR), so, C=10(mu)F`.