A current source sends a current `I=(i_0) cos (omegat)`, When connected across an unknown load, it gives a voltages output of `v=v_(0)sin [omega t+(pi//4)]` across that load. Then the voltage across the current source may bebroaught in phase with the current through it by

Options

A. Connecting an inductor in series with the load
B. Connecting an capactor in series with the load
C. Connecting an inductor in parallel with the load
D. Connecting an capactor in parallel with the load

Answer

A

Explanation

`v=(v_0) sin [ omega t+(pi//4)]=(v_0) cis [0=omega t -(pi//4)]`
Since V lags currents an inductor can bring it in phases with currents.