The voltage time (V-t) graoh for triangular wave having peak value `(V_0)` is as shown in fig.

Options

A. `(V_0)/(sqrt(3))`
B. `(V_0)/(2)`
C. `(V_0)/(sqrt(2))`
D. none of these.

Answer

A

Explanation

`V=(V_0)/(T//4) t, V=(4 V_(0))/(T ) t`
`V_(rms)=sqrt(ltV^(2)gt) (4 V_(0))/(T)sqrt(lt T gt )`
`=(4 V_(0))/(T){(int_(0)^(T//4) t^(2)dt)/(int_(0)^(T//4) dt)}=(V_0)/(sqrt(3)`.