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The power factor of the circuit in fig. ...

The power factor of the circuit in fig. is `1//sqrt(2)`. The capacitance of the circuit is equal to

A

`400(mu)F`

B

`300(mu)F`

C

`500(mu)F`

D

`200(mu)F`

Text Solution

Verified by Experts

The correct Answer is:
C
`cos phi = (R )/(sqrt(R^(2)+((1)/(omwga C)-omega L)^(2))`
Putting the values , `C=500 (mu)F`
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