Home
Class 12
PHYSICS
A series R-C combination is connected to...

A series R-C combination is connected to an AC voltage of angular frequency `omega=500 radian//s`. If the impedance of the R-C circuit is `Rsqrt(1.25)`, the time constant (in millisecond) of the circuit is

Text Solution

Verified by Experts

The correct Answer is:
4

`omega=500 rad s^(-1)`
`Z=sqrt((1)/(omega C)^(2)+R^(2)) = Rsqrt(1.25)`
`(1)/(omega C)^(2)+R^(2)=R^(2)(1.25) implies ((1)/(omega C))^(2) =(R^(2))/(4)`
`implies CR=2/(omega)=(2)/(500) xx (10^3) ms = 4 ms`.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ALTERNATING CURRENT

    CENGAGE PHYSICS|Exercise Single Correct Asnwer Type|27 Videos
  • ALTERNATING CURRENT

    CENGAGE PHYSICS|Exercise Single Correct|10 Videos
  • ALTERNATING CURRENT

    CENGAGE PHYSICS|Exercise Archives Multiple Correct|3 Videos
  • OSCILLATIONS

    CENGAGE PHYSICS|Exercise QUESTION BANK|39 Videos
  • ATOMIC PHYSICS

    CENGAGE PHYSICS|Exercise ddp.4.3|15 Videos

Similar Questions

Explore conceptually related problems

A series R-C combination is connected to an AC voltage of angular frequency omega=500 radian//s . If the impendance of the R-C circuit is Rsqrt(1.25) , the time constant (in millisecond) of the circuit is

A series R-C combination is connected to an AC voltage of angular frequency omega = 500 rad/s. If the impedance of the R-C circuit is R sqrt(1.25) , the time constant (in millisecnd ) of the circuit is

Knowledge Check

  • In a series LCR circuit, operated with an ac of angular frequency omega , the total impedance is

    A
    `[R^(2)+(Lomega-Comega)^(2)]^(1//2)`
    B
    `[R^(2)+(Lomega-1/(Comega))^(2)]^(1//2)`
    C
    `[R^(2)+(Lomega-1/(Comega))^(2)]^(-1//2)`
    D
    `[(Romega)^(2)+(Lomega-1/(Comega))^(2)]^(1//2)`
  • If the impedance of an L-C R circuit is 40 Omega , then the admitance of the circuit will be

    A
    A. 0.1 siemen
    B
    B. 0.025 siemen
    C
    C. 0.05 sieman
    D
    D. 0.075 siemen
  • Series LCR circuit is connected to an AC source of angular frequency omega . Current flowing in the circuit is found to lead the voltage by pi /4. Magnitude of capacitance is

    A
    `(1)/(omega^(2) (L + R))`
    B
    `(1)/(omega (L + R))`
    C
    `(1)/(omega^(2) L + omega R)`
    D
    `(1)/(omega L + omega^(2) R)`
  • Similar Questions

    Explore conceptually related problems

    A series RC combination is connected to an a.c.voltage of angular frequency omega=500rad/s if impedance of the R-C circuit is R sqrt(1.25) ,the time constant (in millisecond) of circuit is...

    In an LCR series combination R= 400 Omega L =100 mH and C = 1 muF . This combination is connected to a 25 sin 2000 t volt voltage source . Find (i) the impedance of the circuit . (ii) the peak value of the ciruit current .

    A series combination of R,LC is connected to an a.c source. If the resistance is 3 Omega and the reactance is 4 Omega , the power factor of the circuit is

    Which increase in frequency of an AC supply , the impedance of an L-C-R series circuit

    In a circuit containing R and L , as the frequency of the impressed AC increase, the impedance of the circuit