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A particle of specific charge q//m = (pi...

A particle of specific charge `q//m = (pi) C//kg` is projected from the origin towards positive x-axis with a velocity of `10 m//s` in a uniform magnetic field `vec(B) = -2 hat K` Tesla. The velocity `vec V` of the particle after time `t =1//6` s will be

A

`(5 hat(i)+5sqrt(3) hat(j))m//s`

B

`10 hat(j)m//s`

C

`(5 sqrt(3)hat(i)+5hat(j))m//s`

D

`-10 hat(j) m//s`

Text Solution

Verified by Experts

The correct Answer is:
A
Time period `T=2 pi (m)/(qB)=1s`
Thus, the praticle will be at P after `t=1/6s`
`:. Vec(V)=10(cos 60 hat(i)+sin60 hat(j))=5(hat(i)+sqrt(3)hat(j))m//s`
Path of electron is shown in fig. Deviation of electron will be `theta=90^(@)`
.
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