Home
Class 12
PHYSICS
The torque experienced by a given curren...

The torque experienced by a given current carrying loop in a uniform magnetic field `vec(B) given by B_(0)(hat i- hat j)` would have magnitude

A

`sqrt(2)B_(0)a^(2)I`

B

zero

C

`2B_(0)a^(2)I`

D

`B_(0)a^(2)I`

Text Solution

Verified by Experts

The correct Answer is:
B

`vec(M)=Ia^(2)[-hat(i)+hat(j)], vec(tau)=vec(M)xxvec(B)`,
Solve to get `tau=0`.
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS VOLUME 5

    CENGAGE PHYSICS|Exercise Multiple Correct|34 Videos
  • MISCELLANEOUS VOLUME 5

    CENGAGE PHYSICS|Exercise Linked Comprehension|84 Videos
  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS|Exercise True and False|3 Videos
  • Moving charges and magnetism

    CENGAGE PHYSICS|Exercise Question Bank|20 Videos

Similar Questions

Explore conceptually related problems

The figure shows a loop of wire carrying a current i as shown. There exists a uniform magnetic field along x-axis given by vec(B) = B_(0) hat(i) . If the length of each side is a, then

A current of 1A is flowing along positive x-axis through a straight wire of length 0.5m placed in a region of a magnetic field given by vec(B)= (2 hat(i) + 4hat(j)) T. The magnitude and the direction of the force experienced by the wire respectively are

A rectangular loop of dimensions (axxb) carries a current i. A uniform magnetic field vec(B)=B_(0) hat(i) exists in space. Then :

A current I amperes flows through a loop abcdefgha along the edge of cube of width l metres as shown in figure. One corner 'a' of the loop lies at origin. Now if a uniform external magnetic field is vec(B) = B_(e) hat(j) is switched on, then the unit vector in the direction of torque due to external magnetic field (vec(B)) acting on the current carrying loop (abcdefgha) is

A wire loop carrying current I is placed in the x-y plane as shown in the figure. If an external uniform magnetic field vec(B)=B hat(i) is switched on, then the torque acting on the loop is

A closed current-carrying loop having a current I is having area A. Magnetic moment of this loop is defined as vec(mu) = vec(IA) where direction of area vector is towards the observer if current is flowing in anticlockwise direction with respect to the observer. If this loop is placed in a uniform magnetic field vec(B) , then torque acting on the loop is given by vec(tau) = vec(mu) xx vec(B) . Now answer the following questions: A uniformly charged insulating ring is rotated in a uniform magnetic field about its own axis, then

A portion is fired from origin with velocity vec(v) = v_(0) hat(j)+ v_(0) hat(k) in a uniform magnetic field vec(B) = B_(0) hat(j) . In the subsequent motion of the proton

A charged particle moves with velocity vec v = a hat i + d hat j in a magnetic field vec B = A hat i + D hat j. The force acting on the particle has magnitude F. Then,