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A small square loop of edge a and resist...

A small square loop of edge a and resistance R is moved with velocity `v_(0)` away from an infinitely long current carrying conductor carrying current I so that the conductor and side of square are always in same plane. Find induced current in loop at a separation of `r`

A

`(mu_(0)ia^(2)v)/(pi r^(2)R)`

B

`(mu_(0)ia^(2)v)/(4pi r^(2)R)`

C

`(mu_(0)ia^(2)v)/(2pi r^(2)R)`

D

`(mu_(0)iav)/(2pi rR)`

Text Solution

Verified by Experts

The correct Answer is:
C
`phi=BA=(mu_(0)i)/(2 pi v t)(a^2)`
`i=-(1)/(R) (d phi)/(dt)=(mu_(0)ia^(2))/(2 pi v t^(2)R)=(mu_(0)ia^(2)v)/(2 pi v t^(2)R)`
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