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In Fig. two air-cored solenoid P and Q h...

In Fig. two air-cored solenoid P and Q have been shown. They are placed near each other. In Fig. when `I_(p)` the current in P, changes at the rate of `5 A//s`, and emf of 2 mV is induced in Q. The current in P is then switched off, and a current changing at `2 A//s` is fed through Q as shown in diagram. What emf will be induced in P?

A

`8xx10^(-4)V`

B

`2xx10^(-3)V`

C

`5xx10^(-3)V`

D

`8xx10^(-2)V`

Text Solution

Verified by Experts

The correct Answer is:
A
The mutual inductance M between solenoid P and Q is given by emf induced in Q due to changing of current `I_(P)` in P)
`2xx10^(-3)=Mxx(5)`
`:. M=4.0xx10^(-4)H`
Similarly, emf induced in P due to changing current in `Q=Mxx("rate of change of current" I_(Q) "in" Q)`
`implies` induced emf in `P=(4.0xx10^(-4))xx(2)=8.0xx10^(-4)V`.
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