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A triangular wire frame (each side =2m) ...

A triangular wire frame (each side =2m) is placed in a region of time variant magnetic field `dB//dt = (sqrt3) T//s`. The magnetic field is perpendicular to the plane of the triangle and its centre coincides with the centre of triangle. The base of the triangle AB has a resistance `1(Omega)` while the other two sides have resistance `2(Omega)` each. The magnitude of potential difference between the points A and B will be

A

0.4 V

B

0.6 V

C

1.2V

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
`e=(d phi)/(dt)=A(dA)/(dt)=1/2 2xx2 sin 60^(@) sqrt(3)=3V`
Induced emf in each side `=e//3`
`1V`
`I=e/R =(3)/(1+2+2)=3/5 A`
`V_(A)+1-Ixx1=V_(B)`
`implies V_(A)-V_(B)=I-1=(-2)/(5)`
`=-0.4V`.
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