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To the right of line PQ is a uniform mag...

To the right of line PQ is a uniform magnetic field `vec(B).B_(1)A` is the line of incidence of a charged particle, which comes out of the field along DE, CA and DF are the normals at A and D. `-B_(1)AC =(theta)`. Angle measured from CA in clockwise direction is taken as positive. What will be the value of `(theta)` so that angle subtended by the part of the circle (along which charged particle moves in the field) at its centre and facing the circle is less than `pi`?

A

`theta` is positive

B

`theta-0`

C

`theta` is negative

D

`theta` depands upon `vec(B)` and change

Text Solution

Verified by Experts

The correct Answer is:
C
The diagrame are self-explanatory
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