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In the circuit shown in Fig. A conductin...

In the circuit shown in Fig. A conducting wire HE is moved with a constant speed v towards left. The complete circuit is placed in a uniform magnetic field `vec(B)` perpendicular to the plane of circuit inwards. The current in HKDE is

A

clockwise

B

anticlockwise

C

direction will change with time

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D
As rod is moving with constant velocity the potential difference across capacitor will remain constnat. Hence no current will flow through capacitor branch.
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