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Fig. Shows a conducting circular loop of...

Fig. Shows a conducting circular loop of radius a placed in a uniform, perpendicular magnetic field B. A thick metal rod OA is pivoted at the centre O. The other end of the rod touches the loop at A. The centre O and a fixed point C on the loop are connected by a wire OC of resistance R. A force is applied at the middle point of the rod OA perpendicularly, so that the rod rotates clockwise at a uniform angular velocity `(omega)`. Find the force.

A

`(omega a^(3)B^(2))/(R)` to the right of OA in the figure

B

`(omega a^(3)B^(2))/(2R)` to the right of OA in the figure

C

`(omega a^(3)B^(2))/(2R)` to the left of OA in the figure

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`e=Bvl = (B xx a xx omega xx a)/(2)`
`i=(Ba^(2) omega)/(2 R)`
`F=ilB = (Ba^(2) omega)/(2 R ) xx a xx B=(B^(2)a^(2)omega)/(2 R)`
towards right of OA.
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