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Find the force acting on rectangular loo...

Find the force acting on rectangular loop PQRST.

A

`(IaB)/(2)`

B

`(IaB)/(sqrt(2))`

C

`(IaBsqrt(3))/(2)`

D

`IaBsqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
Force on TP
`=-F_(loop)=I ab si (90^(@)+60^(@))(iaB)/(2) o`.
`F_(loop) = (IaB)/(2) ox`.
Alternatively
`F_(PQ)=IaB sin (90^(@)+30^(@))ox = IaB (sqrt(3))/(2) ox`
`F_(QP)=I(2a)B sin 30^(@) ox=labox`
`F_(RS)=I(a)B sin 60^(@) ox=IaB (sqrt(3))/(2)` o.
Alternativley
`F_(PQ)=lab sin (90^(@)+30^(@)) ox = IaB(sqrt(3))/(2) ox`
`F_(QP)=I(2a)B sin 30^(@)ox=IaB ox`
`F_(RS)=I(a)B sin 60^(@)ox=IaB (sqrt(3))/(2)` ox.
`F_(ST)=IaB sin (90^(@)+60)o. =(IaB)/(2) o`.
so., `F_(n et)=(IaB)/(2) ox`.
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