Home
Class 12
PHYSICS
The magnetic field inn a region is given...

The magnetic field inn a region is given by `vec B = veck (B_0)/(L) y` where L is a fixed length. A conducting rod of length L lies along the Y - axis between the origin and the point (0,L, 0). If the rod moves with a velocity `v= v_0` , find the emf induced between the ends of the rod.

A

`2 B_(0)v_(0)l`

B

`(B_(0)v_(0)l`

C

`(B_(0)v_(0)l)/(2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C

Consider an element of width dy at a distance y form origin.
Induced emf across its ends is `Bv_(0)dy`, where `B=(B_(0))/(L) y`.
Intergrating from 0 to L, `E=(B_(0)v_(0)l)/(2)`.
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS VOLUME 5

    CENGAGE PHYSICS|Exercise Multiple Correct|34 Videos
  • MISCELLANEOUS VOLUME 5

    CENGAGE PHYSICS|Exercise Linked Comprehension|84 Videos
  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS|Exercise True and False|3 Videos
  • Moving charges and magnetism

    CENGAGE PHYSICS|Exercise Question Bank|20 Videos

Similar Questions

Explore conceptually related problems

The magnetic field inn a region is given by vec B = veck (B_0)/(L) y where L is a fixed length. A conducting rod of length L lies along the Y - axis between the origin and the point (0,L, 0). If the rod moves with a velocity v= v_0 veci, find the emf induced between the ends of the rod.

The magnetic field in a region is given by vecB=B_(0)/Lxhatk where L is a fixed length.A conducting rod of length lies along the X -axis between the origin and the point (L,0,0) .If the rod moves with a velocity vecv=v_(0) hatj the emf induced between the ends of the rod.

There is a conducting rod of length 2L that lies along x-axis from x=-L to x=L . If rod moves with velocity v=v_0hati in the magnetic field vecB=B_0hatk , then induced EMF between ends of rod is

A rod od length l is moving in a vertical plane ( x-y ) when the owest point A of the rod is moved with a velociy v . find the a angular velocity of the rod and b velocity of the end B .

A metal rod of length I is moved with velocity v in a uniform magnetic field vec B . Emf is induced between the two ends of rod

A wire of length 2l is bent at mid point so that the angle between two halves is 60^(@) . If it moves as shown with a velocity v in a magnetic field B find the induced emf.

The magnetic field in a region is given by vec(B)=B_(0)(1+(x)/(a))hat(k) . A square loop of edge length 'd' is placed with its edge along X-axis and Y-axis. The loop is moved with a constant velocity vec(V)=V_(0)hat(i) . The emf induced in the loop is

A conducting rod of length l is rotating with constant angular velocity omega about point O in a uniform magnetic field B as shown in the figure . What is the emf induced between ends P and Q ?

A uniform rod of length l is spinning with an angular velocity omega=2v/l while its centre of mass moves with a velocity v . Find the velocity of the end of the rod.