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The diagram given below shows a solenoid...

The diagram given below shows a solenoid carrying time varying current `l= l_(0)t`. On the axis of the solenoid, a ring has been placed. The mutual inductance of the ring and the solenoid is M and the self inductance of the ring is L. If the resistance of the ring is R then maximum current which can flow through the ring is

A

`((2M+L)I_(0))/(R)`

B

`(MI_(0))/(R)`

C

`((2M-L)I_(0))/(R)`

D

`((M+L)I_(0))/(R)`

Text Solution

Verified by Experts

The correct Answer is:
B
`phi=MI=MI_(0)t`
Hence, induced emf `e=(d phi)/(dt)=MI_(0)`
Current through ring `=e/R=(MI_(0))/(R)`.
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