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A conduting wire ABC (as shown) is movin...

A conduting wire ABC (as shown) is moving with a constant velocity along horizontal direction. The magnetic field is perpendicular to the wire and directed into the page. AB =BC. Find the range of angle `(theta)` made by rod AB with horizontal at A so that value of induced emf at A is greater than at C

A

`thetagt45^(@)`

B

`thetalt45^(@)`

C

`thetagt60^(@)`

D

`thetalt75^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
Let `AB=BC=l`
velocity `=v`
Megnetic filed`=B`

`(E_1)=Bvl sin theta`
`E_(2)=Bvl cos theta`
For induced emf at `A gt` induced emf at B.
`E_(2) gt E_(1)`
`Bv l(cos theta-sin theta) gt 0`
`cos theta gt sin theta implies tan theta ltlt1`
`theta lt 45^(@)`.
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