What will be the following temperatures on the kelvin scale: a. `37^@`, b. `80^@F`, c. `-196^@C`?

Explanation

a. Temperature on kelvin scale `T_k` is related to temperature `T_c` on celsius scale as
`T_k=T_c+273`
or `T_k=37+273=310K`
b. Temperatures `T_k` on kelvin scale and `T_F` on Fahrendeit scale are related as
`(T_k-273)/(373-273)=(T_F-32)/(212-32)`
or `(T_k-273)/(100)=(T_F-32)/(180)`
or `T_k=(5)/(9)(T_F-32)+273`
here `T_F=80^@F`, thus
`T_k=(5)/(9)(80-32)+273=299.66K`
c. Again from relation used in part (a)
`T_k=T_c+273=-196+273=77K`