Home
Class 11
PHYSICS
The temperature of a silver bar rised by...

The temperature of a silver bar rised by `10.0^@`C when it absorbs `1.23kJ` of energy by heat. The mass of bar is 525g. Determine the specific heat of silver.

A

`294J//kg^@C`

B

`234J//kg^@C`

C

`334J//kg^@C`

D

`394J//kg^@C`

Text Solution

Verified by Experts

The correct Answer is:
B
We find its specific heat from the definition, which is contained in the equation `Q=mc_(silver)DeltaT` For energy input by heat to produce a temperature change. Solving we have
`c_(silver)=(Q)/(mDeltaT)`
`c_(silver)=(1.23xx10^3J)/((0.525kg)(10.0C))=234J//kg.^@C`
Promotional Banner

Topper's Solved these Questions

  • CALORIMETRY

    CENGAGE PHYSICS|Exercise Exercise 1.1|23 Videos

  • CALORIMETRY

    CENGAGE PHYSICS|Exercise Exercise 1.2|22 Videos

  • BASIC MATHEMATICS

    CENGAGE PHYSICS|Exercise Exercise 2.6|20 Videos

  • CENTRE OF MASS

    CENGAGE PHYSICS|Exercise INTEGER_TYPE|1 Videos

Similar Questions

Explore conceptually related problems

When two heating devices are used to heat two different substance A and B the heat absorbed by A after 2 seconds is found to be equal to the heat absorbed byy B after 3 seconds. The rise in temperature of A after 5 seconds is found to be equal to the rise in temperature of B after 6 seconds.i the ratio of masses o A and B is 1:2, determine the ratio of the specific heat capacities of two substances.

How much heat (in joule) is required to raise the temperature of 205 g of water from 21.2^(@)C to 91.4^(@)C . Specific heate of water is 4.18 J g^(-1) .^(@)C^(-1) Strategy : The specific heat of a substance is the amount of heat required to raise the temperature of 1g of the substance by 1^(@C . Thus Specific heat = (("Amount of heat in joules"))/(("Mass of substance in grams")("Temperature change in" .^(@)C)) Rearrangement gives. Amount of heat (q) = Mass of substance (m) xx Specific heat (c ) xx Temperature change (Delta T)

50 g of copper is heated to increase its temperature by 10^@C . If the same quantity of heat is given to 10g of water, the rise in its temperature is (specific heat of copper =420J//kg^(@)//C )

The amount of heat absorbed by a body while raising its temperature is given by the equation. Q = mstheta , here Q is the amount of heat, m is the mass of the body, s is the specific heat capacity and theta is the rise tmemperature. Dertermine the S.I. unit and C.G.S. unit of heat and specific heat capacity

In an experiment to determine the specific heat of aluminium, piece of aluminimum weighing 500 g is heated to 100 .^(@) C . It is then quickly transferred into a copper calorimeter of mass 500 g containing 300g of water at 30 .^(@) C . The final temperature of the mixture is found to be 146.8 .^(@) c . If specific heat of copper is 0.093 cal g^-1 .^(@) C^-1 , then the specific heat aluminium is.