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A hot black body emits the energy at the...

A hot black body emits the energy at the rate of 16 `Jm^-2s^-1` and its most intense radiation corresponds to 20000`Å`. When the temperature of this body is further increased and its most intense radiation corresponds to `10000Å`, then find the value of energy radiated in `Jm^-2s^-1`.

A

258

B

256

C

196

D

225

Text Solution

Verified by Experts

The correct Answer is:
B
Wein's displacement law is
`lamda_m=T=b` i.e. `Tprop(1)/(lamda_m)`
Here, `lamda_m` becomes half, so temperature doubles.
also `e=sigmaT_4`
`implies(e_1)/(e_2)=((T_1)/(T_2))^4`
`impliese_2=((T_1)/(T_2))^4e_1=(2)^4xx16=16xx16=256Jm^-2s^-1`
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