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Three rods of identical cross-sectional area and made from the same metal from the sides of an isosceles triangle ABC, right-angled at B. The point A and B are maintained at temperatures T and `sqrt(2)` T respectively. In the steady state, the temperature of the point C is `T_c.` Assuming that only heat conduction takes places, `T_c//T` is

A

`(1)/(2(sqrt2-1))`

B

`(3)/(sqrt 2+1)`

C

`(1)/(sqrt3(sqrt2-1))`

D

`(1)/(sqrt2+1)`

Text Solution

Verified by Experts

The correct Answer is:
B

`((DeltaQ)/(Delta))_(BC)=((DeltaQ)/(Deltat))_(CA)`
`implies (kA(sqrt(2T)-T_(C)))/(a)=(kA(T_(C)-T))/(sqrt(2a))`
Solve to get
`(T_(C))/(T)=(3)/(sqrt(2)+1)`
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