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For an ideal gas :...

For an ideal gas :

A

The change in internal energy in a constant pressure process from temperature `T_1` to `T_2` is equal to `nCv(T_2-T_1)`, where Cv is the molar specific heat at constant volume and n the number of moles of the gas.

B

The change in internal energy of the gas and the work done by the gas are equal in magnitude in an adiabatic process.

C

The internal energy does not change in an isothermal process.

D

No heat is added or removed in an adiabatic process.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
`DeltaU=nC_(v)DeltaT rarr` for any process
In adiabatic process: `DeltaQ=0` , so `DeltaU=-Deltaw implies |DeltaU|=|Deltaw|`
In isothemal process, `DeltaT=0` , so `DeltaU=0`
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Knowledge Check

  • For two mole of an ideal gas :

    A
    `C_(v)-C_(p)=R`
    B
    `C_(p)-C_(v) = 2R`
    C
    `C_(p)-C_(v) = R`
    D
    `C_(v)-C_(p) = 2R`

  • During the isothermal of an ideal gas :

    A
    The internal energy remains unaffected
    B
    The temperature remains constant
    C
    The enthalpy remains unaffected
    D
    The enthalpy increases

  • The compressibility factor an ideal gas is

    A
    1.5
    B
    `1.0`
    C
    `2.0`
    D
    `oo`