The temperature of an ideal gas is increased from 120K to 480K. If at 120K the root-mean-squre velocity of the gas molecules is v, at 480K it becomes

Options

A. `4v`
B. `2v`
C. `v//2`
D. `v//4`

Answer

B

Explanation

`v_("rms")=sqrt((3RT)/(M))`
`v_("rms")propsqrt(T)`
When temperature is increased from `120K` to `480K` (i.e., four times), the root mean square speed will become `sqrt(4)` or `2` times, `i.e., `2v` .