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Two identical rods are connected between two containers one of them is at `100^@C` and another is at `0^@C.` If rods are connected in parrallel, then the rate of melting of ice is `q_1 gm//sec.`
If they are connected in series then the rate is `q_2.` The ratio `q_2//q_1` is

A

2

B

4

C

`1//2`

D

`1//4`

Text Solution

Verified by Experts

The correct Answer is:
D

`q_(1)=(K2A(100))/(l)`
`q_(2)=(A(100))/((l)/(k)+(l)/(k))=(KA(100))/(2l)`
`:. (q_(2))/(q_(1))=(KA(100))/(2l)xx(l)/(K2A(100))=(1)/(4)`
.
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