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A mixture of 2 moles of helium gas ((ato...

A mixture of 2 moles of helium gas (`(atomic mass)=4a.m.u`) and 1 mole of argon gas (`(atomic mass)=40a.m.u`) is kept at 300K in a container. The ratio of the rms speeds `((v_(rms)(helium))/((v_(rms)(argon))` is

A

`0.32`

B

`0.45`

C

`2.24`

D

`3.16`

Text Solution

Verified by Experts

The correct Answer is:
D
`(v_("rms"_(He)))/(v_("rms"_(Ar)))=sqrt((2RT)/(m_(He)))/(sqrt((3RT)/(m_(Ar))))=sqrt((m_(Ar))/(m_(He)))=sqrt((40)/(4))=sqrt(10)~~3.16`
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