A particle free to move along the (x - axis) hsd potential energy given by `U(x)= k[1 - exp(-x^2)] for -o o le x le + o o`, where (k) is a positive constant of appropriate dimensions. Then.

Answer

A

Explanation

Since `F=-(dU)/(dx)=2kxexp(-x)^2`
`F=0` (at equilibrium as `x=0`)
U is minimum at `x=0` and `U_(min)=0`
`U` is maximum `xrarr+-infty` and `U_(max)=k`
The particle would oscillate about `x=0` for small displacement from the origin and it is in stable equalibrium at the origin.