The metallic bob of a simple pendulum has the relative density `rho`. The time period of this pendulum is `T` if the metallic bob is immersed in water the new time period is given by

Options

A. `2pisqrt((l)/(ng))`
B. `2pisqrt((l)/((1-(1)/(n))g))`
C. `2pisqrt((ln)/(g))`
D. `2pisqrt((l)/((n-1)g))`

Answer

B

Explanation

As discussed in theory part
`T=2pisqrt((l)/(g(1-(rho)/(sigma))))`
`rho=`density of liquid
`sigma=`density of bob material
Given `rho=(sigma)/(n)`
hence period is `2pisqrt((l)/(1-((1)/(n))g))`