A particle is performing SHM. Its kinetic energy K varies with time t as shown in the figure. Then

Options

A.
Period of oscillation of the particle is equal to T.
B. excess potential energy `U` of the particle varies with time t as shown in Fig.
C. excess potential energy U of the particle varies with time t as shown in fig.
D. none of these

Answer

B

Explanation

When a particle performs SHM, its total energy remains constant. It means, kinetic energy plus excess potential energy is a constant, which is equal to maximum possible kinetic energy.
Hence, excess potential energy will be maximum when KE is equal to zero and zero when KE is maximum possible. Hence option (b) is correct. If frequency of oscillations of a particle is equal to `n`, then frequency of veriation of its KE is equal to T, then time period of oscillations of the particle will be equal to 2T. Hence option (a) is wrong.