The time taken by a particle performing `SHM` on a straight line to pass from point `A` to `B` where its velocities are same is `2` seconds .After another `2` seconds it return to `B` The time period of oscillation is (in seconds)

Options

A. 2 s
B. 4 s
C. 6 s
D. 8 s

Answer

D

Explanation

The situation is illustrated if Fig. `t_2-t_1=2s`,`t_3-t_2=2s`
i.e., `t_3-t_1=4s`which is half of the time period.
So, `T=8s`