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In the previous question, the magnitude ...

In the previous question, the magnitude of velocity of particle at the mentioned instant is

A

`(piA)/(T)`

B

`(sqrt2piA)/(T)`

C

zero

D

`sqrt((7)/(8))xx(2piA)/(T)`

Text Solution

Verified by Experts

The correct Answer is:
B

Velocity at any displacement `x` is given by
`v=omegasqrt(A^2-x)`
So, the required velocity `=(2pi)/(T)sqrt(A^2-(A^2)/(2))=(sqrt2piA)/(T)`
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