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A particle is performing SHM according t...

A particle is performing `SHM` according to the equation `x=(3cm)sin((2pi)/(18)+(pi)/(6))`, where t is in seconds. The distance travelled by the particle in 39 s is

A

`24 cm`

B

`1.5 cm`

C

`25.5 cm`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C

The time period of simple harmonic motion is `T=18s`.
At `t=0` the particle is at `x=(3)/(2)`cm and approaching position extreme.
`39s=2xx18+3=2T+3=2T+(T)/(6)`
distance travelled by the particle is `2T` is `8A=24cm`.
distance travelled by the particle in further
`(T)/(6)` is `(A)/(2)=1.5cm`.
Total distance travelled`=25.5cm`
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