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A physical pendulum is positioned so tha...

A physical pendulum is positioned so that its centre of gravity is above the suspension point. When the pendulum is realsed it passes the point of stable equilibrium with an angular velocity `omega`. The period of small oscollations of the pendulum is

A

`(4pi)/(omega)`

B

`(2pi)/(omega)`

C

`(pi)/(omega)`

D

`(pi)/(2omega)`

Text Solution

Verified by Experts

The correct Answer is:
A

`(1)/(2)Iomega^2=mg(2l)implies(I)/(mgl)=(4)/(omega^2)`
`T=2pisqrt((I)/(mgl))=2pisqrt((4)/(omega^2))=(4pi)/(omega)`
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