In the above question, the speed of the particle at origin will be:

Options

A. `10sqrt2(m)/(s)`
B. `1.5(m)/(s)`
C. `10(m)/(s)`
D. none of these

Answer

A

Explanation

`v(dv)/(dx)=-100x+50`
`impliesintvdv=int(50-100x)dx`
`implies(v^2)/(2)=50x-(100x^2)/(2)+c`
At `x=2` , `v=0`
`0=100-200+cimpliesc=100`,
`v^2=2[50x-(100x^2)/(2)+100]`
At `x=0`
`v=sqrt(2[100])`
`=10sqrt2(m)/(s)`