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A plank with a small block on top of it ...

A plank with a small block on top of it is under going vertical `SHM`. Its period is `2 sec`. The minimum amplitude at which the block will separate from plank is :

A

`(10)/(pi^2)`

B

`(pi^2)/(10)`

C

`(20)/(pi^2)`

D

`(20)/(pi^2)`

Text Solution

Verified by Experts

The correct Answer is:
A

Here `g=Aomega^2`
`A=(g)/(omega^2)=(g)/(((2pi)/(T))^2)=(gT^2)/(4pi^2)`
`=(10xx4)/(4pi^2)=(10)/(pi^2)m`
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