The displacement of a body executing `SHM` is given by `x=A sin (2pi t+pi//3)`. The first time from `t=0` when the velocity is maximum is

Options

A. 0.33 s
B. 0.16 s
C. 0.25 s
D. 0.5 s

Answer

A

Explanation

`v=(dx)/(dt)=2piAcos(2pit+(pi)/(3))`
or `+-2piA=2piAcos(2pit+(pi)/(3))`
or `cos(2pit+(pi)/(3))=-1`
Hence `theta=(pi)/(2)-(pi)/(3)`
`=(3pi-2pi)/(6)`
`theta=omegat_0` or
`(pi)/(6)=2pit_0` `therefore` `t_0=(pi)/(12pi)=(1)/(12)sec`